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IU men’s tennis takes in last home matches of season



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Then-junior Antonio Cembellin, now a senior, celebrates after winning a point during his 1-6, 6-3, 4-6 loss to Wisconsin on April 8, 2018, at the IU Tennis Center. IU will face Nebraska on Saturday. Sam House Buy Photos

Coinciding with the Little 500, IU men’s tennis will play its last home matches of the season in Bloomington.

Nebraska will be the first to get a crack at IU this weekend. The first serve will be at noon on Saturday, two hours before the Little 500 men’s race begins.

The Huskers come into the match with a 9-13 record overall, going just 1-6 in the Big Ten so far. Nebraska is coming off a four-match losing streak, but IU Head Coach Jeremy Wurtzman knows its potential.

“We’re gonna focus in on Saturday first,” Wurtzman said. “Nebraska beat Minnesota this year and have had some pretty good results.”

IU fell to Minnesota 5-2 last weekend, whereas Nebraska took them down just a few weeks ago.

This will be the first time IU plays two matches in one day since Jan. 13 against University of Toledo and Ball State University. IU was scheduled to play two matches Feb. 1, but the earlier match with Wright State University was canceled.

No. 46 Iowa and St. Louis University will make their way to Bloomington for some Sunday tennis. IU will take on Iowa at noon and St. Louis at 5 p.m.

The Hawkeyes moved into the rankings this week after taking down then-No. 30 Penn State on April 5, moving them to 13-7 overall.

After the Hoosiers take on the Hawkeyes, they'll get the Billikens for their final home match of the season. St. Louis is just 2-9 with its only wins coming against Quincy University and McKendree University.  

All three matches will take place at the IU Tennis Center this weekend.

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